If it's not what You are looking for type in the equation solver your own equation and let us solve it.
36x^2-90x+25=0
a = 36; b = -90; c = +25;
Δ = b2-4ac
Δ = -902-4·36·25
Δ = 4500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4500}=\sqrt{900*5}=\sqrt{900}*\sqrt{5}=30\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-30\sqrt{5}}{2*36}=\frac{90-30\sqrt{5}}{72} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+30\sqrt{5}}{2*36}=\frac{90+30\sqrt{5}}{72} $
| 2(p-5)=2(10+2p)+ | | x+40+3x+10+6x=x | | (7x+19)+(11x+89)+60+60=180 | | 2/11=12/b | | 8-51/4n=-7/8 | | -6(3x+15)=18;x= | | {x}{-6}-8=-6 | | 20/x=5.2/6.5 | | (2.66)(.40x)=(x)(1.24) | | -1/4x-300=-50 | | -6(3x+15)=18;x | | x/2−9=−20 | | 10x-31=61 | | n/27=1/3 | | c/7=56 | | 5(3k-3)=90 | | x^2-16=2x^2-80 | | (4x+8)+x+x=180 | | -16.7=2x=3 | | 3+0.5n=2×n+14 | | 2x-84=28-6x | | 23x+23x+18=180 | | (2x-13)=(3x-21) | | 1/3=n/27 | | 30+4x+2+6x+8=180 | | 25x–17=0 | | x/7−3=−10 | | 9(2/5)=8(7/x) | | -27x-10=-1441 | | 28+7s=-7 | | 9+v=-20 | | 14v=644 |